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Populating function inputs from lists
Don't understand why Do-loop index is not evaluated in Play expressionPiecewise function with user-input intervalDefining a function in terms of matrix elementsHow do I define a collections of commands for later use？How to define a function which takes another function as input in ModuleSame function but in different variablesHow to recall set variables in simple Product[] and Sum[] functions?Is there a way to Connect a function ''normally'' through its Pole?solving an equation for two lists of values sequentiallyProblem faced using user-defined mod function in loop
$begingroup$
I have several lists containing variables, e.g. list1=x1,x2,x3, list2=y1,y2,y3, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked 8 hours ago
BranBran
1315
$endgroup$
add a comment |
$begingroup$
I have several lists containing variables, e.g. list1=x1,x2,x3, list2=y1,y2,y3, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked 8 hours ago
BranBran
1315
$endgroup$
add a comment |
$begingroup$
I have several lists containing variables, e.g. list1=x1,x2,x3, list2=y1,y2,y3, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked 8 hours ago
BranBran
1315
$endgroup$
I have several lists containing variables, e.g. list1=x1,x2,x3, list2=y1,y2,y3, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
functions procedural-programming
asked 8 hours ago
BranBran
1315
asked 8 hours ago
BranBran
1315
asked 8 hours ago
BranBran
1315
asked 8 hours ago
BranBran
1315
asked 8 hours ago
BranBran
1315
1315
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = x1, x2, x3; list2 = y1, y2, y3;
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = list1, list2
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 7 hours ago
MarcoB
38.4k557115
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
8 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
8 hours ago
|
show 1 more comment
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = x1, x2, x3; list2 = y1, y2, y3;
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = list1, list2
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 7 hours ago
MarcoB
38.4k557115
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
8 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
8 hours ago
|
show 1 more comment
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = x1, x2, x3; list2 = y1, y2, y3;
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = list1, list2
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 7 hours ago
MarcoB
38.4k557115
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
8 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
8 hours ago
|
show 1 more comment
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = x1, x2, x3; list2 = y1, y2, y3;
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = list1, list2
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 7 hours ago
MarcoB
38.4k557115
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
$endgroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = x1, x2, x3; list2 = y1, y2, y3;
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = list1, list2
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 7 hours ago
MarcoB
38.4k557115
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
edited 7 hours ago
MarcoB
38.4k557115
edited 7 hours ago
MarcoB
38.4k557115
edited 7 hours ago
MarcoB
38.4k557115
38.4k557115
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
answered 8 hours ago
Slepecky MamutSlepecky Mamut
700111
700111
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
8 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
8 hours ago
|
show 1 more comment
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
8 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
8 hours ago
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,
f[x1, x2, x3, y1, y2, y3]...$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran it gives exactly what you asked for,
f[x1, x2, x3, y1, y2, y3]...$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Like
f[z1,z2,x1,x2,x3,y1,y2,y3].$endgroup$
– Bran
8 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Like
f[z1,z2,x1,x2,x3,y1,y2,y3].$endgroup$
– Bran
8 hours ago
1
1
$begingroup$
@Bran
f[whatever, ##, whatever2]& @@ ...$endgroup$
– Kuba♦
8 hours ago
$begingroup$
@Bran
f[whatever, ##, whatever2]& @@ ...$endgroup$
– Kuba♦
8 hours ago
|
show 1 more comment
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