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Finding the reason behind the value of the integral.


Not sure how to solve this integralTI Nspire CX CAS fails to perfrom basic integrationIndefinite integral of absolute valueHelp with Differentiating through the Integral SignInitial value problem without explicit constant findingDefinite integration using even and odd functionsEvaluating a real definite integral using residue theoremHow to plot the graph of $[|sin x|+|cos x|]$ where [.] is the G.I.F?Definite integral involving polylogarithmWhy can't the indefinite integral $intfracsin(x)xmathrm dx$ be found?













12












$begingroup$


I was just trying to find $$int_0^pi / 2fracsin9xsinx,dx $$ using an online integral calculator. And surprisingly I found that if I replace $9x$ by $ x,3x,5x$ which are some odd multiples of $x$ the value of integral came out to be $dfrac pi 2$.



I can't figure out the reason and would like to know why this is happening.










share|cite|improve this question











$endgroup$







  • 7




    $begingroup$
    The following identity seems like it may help:$$fracsin((n+1/2)thetasin(theta/2)=1+2cos x+2cos(2x)+cdots+2cos(nx).$$ (This is known as the Dirichlet kernel, and a proof may be found at the corresponding Wikipedia page here.)
    $endgroup$
    – Semiclassical
    5 hours ago
















12












$begingroup$


I was just trying to find $$int_0^pi / 2fracsin9xsinx,dx $$ using an online integral calculator. And surprisingly I found that if I replace $9x$ by $ x,3x,5x$ which are some odd multiples of $x$ the value of integral came out to be $dfrac pi 2$.



I can't figure out the reason and would like to know why this is happening.










share|cite|improve this question











$endgroup$







  • 7




    $begingroup$
    The following identity seems like it may help:$$fracsin((n+1/2)thetasin(theta/2)=1+2cos x+2cos(2x)+cdots+2cos(nx).$$ (This is known as the Dirichlet kernel, and a proof may be found at the corresponding Wikipedia page here.)
    $endgroup$
    – Semiclassical
    5 hours ago














12












12








12


6



$begingroup$


I was just trying to find $$int_0^pi / 2fracsin9xsinx,dx $$ using an online integral calculator. And surprisingly I found that if I replace $9x$ by $ x,3x,5x$ which are some odd multiples of $x$ the value of integral came out to be $dfrac pi 2$.



I can't figure out the reason and would like to know why this is happening.










share|cite|improve this question











$endgroup$




I was just trying to find $$int_0^pi / 2fracsin9xsinx,dx $$ using an online integral calculator. And surprisingly I found that if I replace $9x$ by $ x,3x,5x$ which are some odd multiples of $x$ the value of integral came out to be $dfrac pi 2$.



I can't figure out the reason and would like to know why this is happening.







definite-integrals






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 4 hours ago









Abcd

3,16431339




3,16431339










asked 5 hours ago









JasmineJasmine

368213




368213







  • 7




    $begingroup$
    The following identity seems like it may help:$$fracsin((n+1/2)thetasin(theta/2)=1+2cos x+2cos(2x)+cdots+2cos(nx).$$ (This is known as the Dirichlet kernel, and a proof may be found at the corresponding Wikipedia page here.)
    $endgroup$
    – Semiclassical
    5 hours ago













  • 7




    $begingroup$
    The following identity seems like it may help:$$fracsin((n+1/2)thetasin(theta/2)=1+2cos x+2cos(2x)+cdots+2cos(nx).$$ (This is known as the Dirichlet kernel, and a proof may be found at the corresponding Wikipedia page here.)
    $endgroup$
    – Semiclassical
    5 hours ago








7




7




$begingroup$
The following identity seems like it may help:$$fracsin((n+1/2)thetasin(theta/2)=1+2cos x+2cos(2x)+cdots+2cos(nx).$$ (This is known as the Dirichlet kernel, and a proof may be found at the corresponding Wikipedia page here.)
$endgroup$
– Semiclassical
5 hours ago





$begingroup$
The following identity seems like it may help:$$fracsin((n+1/2)thetasin(theta/2)=1+2cos x+2cos(2x)+cdots+2cos(nx).$$ (This is known as the Dirichlet kernel, and a proof may be found at the corresponding Wikipedia page here.)
$endgroup$
– Semiclassical
5 hours ago











1 Answer
1






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oldest

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8












$begingroup$

Hint




Consider $I(n)=int_0^pi/2 fracsin(nx)sin x dx$




$$I(2m+1)-I(2m-1)=int_0^pi/2 fracsin(2m+1)x-sin(2m-1)xsinx dx=int_0^pi/2 frac2sin(x)cos(2mx)sinx dx$$
$$implies 2int_0^pi/2 cos(2mx)dx$$
Now think what happens to this integral when $m$ is an integer.
And also try to use the fact $I(1)=fracpi2$.






share|cite|improve this answer











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    1 Answer
    1






    active

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    1 Answer
    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes









    8












    $begingroup$

    Hint




    Consider $I(n)=int_0^pi/2 fracsin(nx)sin x dx$




    $$I(2m+1)-I(2m-1)=int_0^pi/2 fracsin(2m+1)x-sin(2m-1)xsinx dx=int_0^pi/2 frac2sin(x)cos(2mx)sinx dx$$
    $$implies 2int_0^pi/2 cos(2mx)dx$$
    Now think what happens to this integral when $m$ is an integer.
    And also try to use the fact $I(1)=fracpi2$.






    share|cite|improve this answer











    $endgroup$

















      8












      $begingroup$

      Hint




      Consider $I(n)=int_0^pi/2 fracsin(nx)sin x dx$




      $$I(2m+1)-I(2m-1)=int_0^pi/2 fracsin(2m+1)x-sin(2m-1)xsinx dx=int_0^pi/2 frac2sin(x)cos(2mx)sinx dx$$
      $$implies 2int_0^pi/2 cos(2mx)dx$$
      Now think what happens to this integral when $m$ is an integer.
      And also try to use the fact $I(1)=fracpi2$.






      share|cite|improve this answer











      $endgroup$















        8












        8








        8





        $begingroup$

        Hint




        Consider $I(n)=int_0^pi/2 fracsin(nx)sin x dx$




        $$I(2m+1)-I(2m-1)=int_0^pi/2 fracsin(2m+1)x-sin(2m-1)xsinx dx=int_0^pi/2 frac2sin(x)cos(2mx)sinx dx$$
        $$implies 2int_0^pi/2 cos(2mx)dx$$
        Now think what happens to this integral when $m$ is an integer.
        And also try to use the fact $I(1)=fracpi2$.






        share|cite|improve this answer











        $endgroup$



        Hint




        Consider $I(n)=int_0^pi/2 fracsin(nx)sin x dx$




        $$I(2m+1)-I(2m-1)=int_0^pi/2 fracsin(2m+1)x-sin(2m-1)xsinx dx=int_0^pi/2 frac2sin(x)cos(2mx)sinx dx$$
        $$implies 2int_0^pi/2 cos(2mx)dx$$
        Now think what happens to this integral when $m$ is an integer.
        And also try to use the fact $I(1)=fracpi2$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 34 mins ago

























        answered 5 hours ago









        NewBornMATHNewBornMATH

        44410




        44410



























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