Greatest common substringShortest Longest Common Subsequence CodeDecompose a StringGiven a string find the substring which appears most oftenFind Patterns in StringsShortest Longest Common Subsequence CodeMaximal Substring ConstructionVisualize the greatest common divisorShortest Unique SubstringAs Easy As A-B-CFind the original string, without the repetition without the repetition in the middleThe Third String
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Greatest common substring
Shortest Longest Common Subsequence CodeDecompose a StringGiven a string find the substring which appears most oftenFind Patterns in StringsShortest Longest Common Subsequence CodeMaximal Substring ConstructionVisualize the greatest common divisorShortest Unique SubstringAs Easy As A-B-CFind the original string, without the repetition without the repetition in the middleThe Third String
$begingroup$
Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.
- This may mean outputting the empty string.
- If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.
- There will always be at least one string in the input, but there might not be a non-empty string.
- All printable ASCII characters may appear in the input. You may assume those are the only characters that appear.
- You may take input or produce output by any of the default methods.
Standard loopholes aren't allowed.- This is code-golf - the fewer bytes of code, the better.
Test cases:
[Inputs] -> [Valid outputs (choose one)]
["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]
["%%not&", "ju&#st", "[&]alpha_numeric"] -> ["%"]
code-golf string subsequence
$endgroup$
add a comment |
$begingroup$
Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.
- This may mean outputting the empty string.
- If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.
- There will always be at least one string in the input, but there might not be a non-empty string.
- All printable ASCII characters may appear in the input. You may assume those are the only characters that appear.
- You may take input or produce output by any of the default methods.
Standard loopholes aren't allowed.- This is code-golf - the fewer bytes of code, the better.
Test cases:
[Inputs] -> [Valid outputs (choose one)]
["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]
["%%not&", "ju&#st", "[&]alpha_numeric"] -> ["%"]
code-golf string subsequence
$endgroup$
$begingroup$
Possible duplicate
$endgroup$
– Adám
2 hours ago
$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob♦
2 hours ago
1
$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
1 hour ago
$begingroup$
@EmbodimentofIgnorance All printable ASCII characters can appear in the input.
$endgroup$
– Sara J
48 mins ago
add a comment |
$begingroup$
Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.
- This may mean outputting the empty string.
- If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.
- There will always be at least one string in the input, but there might not be a non-empty string.
- All printable ASCII characters may appear in the input. You may assume those are the only characters that appear.
- You may take input or produce output by any of the default methods.
Standard loopholes aren't allowed.- This is code-golf - the fewer bytes of code, the better.
Test cases:
[Inputs] -> [Valid outputs (choose one)]
["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]
["%%not&", "ju&#st", "[&]alpha_numeric"] -> ["%"]
code-golf string subsequence
$endgroup$
Create a program or function which takes a list of strings as input, and outputs the longest string that is a substring of all input strings. If there are several substrings of equal length, and no longer substring, output any one of them.
- This may mean outputting the empty string.
- If there are several valid outputs, you may output any one of them. You are not required to give consistent outpput for a given input so long as the output is always valid.
- There will always be at least one string in the input, but there might not be a non-empty string.
- All printable ASCII characters may appear in the input. You may assume those are the only characters that appear.
- You may take input or produce output by any of the default methods.
Standard loopholes aren't allowed.- This is code-golf - the fewer bytes of code, the better.
Test cases:
[Inputs] -> [Valid outputs (choose one)]
["hello", "'ello"] -> ["ello"]
["very", "much", "different"] -> [""]
["empty", "", "STRING"] -> [""]
["identical", "identical"] -> ["identical"]
["string", "stRIng"] -> ["st", "ng"]
["this one", "is a substring of this one"] -> ["this one"]
["just one"] -> ["just one"]
["", "", ""] -> [""]
["many outputs", "stuptuo ynam"] -> ["m", "a", "n", "y", " ", "o", "u", "t", "p", "s"]
["many inputs", "any inputs", "ny iii", "yanny"] -> ["ny"]
["%%not&", "ju&#st", "[&]alpha_numeric"] -> ["%"]
code-golf string subsequence
code-golf string subsequence
edited 43 mins ago
Sara J
asked 2 hours ago
Sara JSara J
1715
1715
$begingroup$
Possible duplicate
$endgroup$
– Adám
2 hours ago
$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob♦
2 hours ago
1
$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
1 hour ago
$begingroup$
@EmbodimentofIgnorance All printable ASCII characters can appear in the input.
$endgroup$
– Sara J
48 mins ago
add a comment |
$begingroup$
Possible duplicate
$endgroup$
– Adám
2 hours ago
$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob♦
2 hours ago
1
$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
1 hour ago
$begingroup$
@EmbodimentofIgnorance All printable ASCII characters can appear in the input.
$endgroup$
– Sara J
48 mins ago
$begingroup$
Possible duplicate
$endgroup$
– Adám
2 hours ago
$begingroup$
Possible duplicate
$endgroup$
– Adám
2 hours ago
$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob♦
2 hours ago
$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob♦
2 hours ago
1
1
$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
1 hour ago
$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
1 hour ago
$begingroup$
@EmbodimentofIgnorance All printable ASCII characters can appear in the input.
$endgroup$
– Sara J
48 mins ago
$begingroup$
@EmbodimentofIgnorance All printable ASCII characters can appear in the input.
$endgroup$
– Sara J
48 mins ago
add a comment |
8 Answers
8
active
oldest
votes
$begingroup$
Jelly, 12 bytes
Ẇ€œ&/LÐṀḢ¹L?
Try it online!
Last four bytes are there because of the requirement to only output one answer.
$endgroup$
add a comment |
$begingroup$
Brachylog (v2), 3 bytes
sᵛw
Try it online!
Full program. Input from standard input (as a JSON-style list of strings), output to standard output.
Explanation
sᵛw
s Find a substring
ᵛ of every element of the input; the same one for each
w and output it.
Tiebreak order here is set by the s
, favouring the longest substring (the secondary tiebreak doesn't matter, but IIRC it's position within the first element of the input).
Brachylog's s
doesn't return empty substrings, so we need a bit of a trick to get around that: instead of making a function submission (which is what's normally done), we write a full program, outputting to standard output. That way, if there's a common substring, we just output it, and we're done. If there isn't a common substring, the program errors out – but it still prints nothing to standard output, thus it outputs the null string as intended.
$endgroup$
add a comment |
$begingroup$
Python 3, 137 bytes
def a(b):c=[[d[f:e]for e in range(len(d)+1)for f in range(e+1)]for d in b];return max([i for i in c[0]if all(i in j for j in c)],key=len)
Try it online!
New contributor
$endgroup$
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
$endgroup$
– Shieru Asakoto
1 hour ago
$begingroup$
@ShieruAsakoto Oops yeah.
$endgroup$
– Artemis Fowl
1 hour ago
$begingroup$
@JoKing tio.run/…
$endgroup$
– Artemis Fowl
39 mins ago
$begingroup$
@JoKing The one currently in my answer is fine for all the test cases.
$endgroup$
– Artemis Fowl
33 mins ago
$begingroup$
Right, here's a fixed version of the 135 byte program
$endgroup$
– Jo King
29 mins ago
add a comment |
$begingroup$
Perl 6, 62 bytes
~sort(-*.comb,keys [∩] .map(*.comb[^*X.. ^*+1]>>.join))[0]
Try it online!
I'm a little annoyed the Perl 6 can't do set operations on lists of lists, which is why there's an extra .comb
and >>
in there. Another annoying thing is that max
can't take an function for how to compare items, meaning I have to user sort
instead.
$endgroup$
add a comment |
$begingroup$
Japt v2.0a0, 24 bytes
mã c f@eøXÃr@XÊ>YÊ?X:Y}P
This is a mess. Why isn't there a max function for arrays in Japt?
Try it online!
$endgroup$
add a comment |
$begingroup$
Zsh, 126 bytes
for l in $@
a=
for i in 0..$[$#l**2]
a+=($l[1+i/$#l,1+i%$#l])
b=($$b-$a:*a)
for i in $b
(($#x<$#i))&&x=$i
<<<$x
Try it online!
We read all possible substrings into $a
, and then intersect the common elements of $a
and $b
.
for l in $@;
a= # unset a
for i in 0..$[$#l**2]; # compound double loop using div/mod
a+=( $l[1+i/$#l,1+i%$#l] ) # append to a all possible substrings of the given line
b=( $$b-$a:*a )
# $b-$a # if b is unset substitute $a
# $ :*a # take common elements of $b-$a and $a
# b=( ) # set b to those elements
for i in $b; # for every common substring
(( $#x < $#i ))&&x=$i # if the current word is longer, use it
<<<$x # print to stdout
New contributor
$endgroup$
add a comment |
$begingroup$
Python 2, 103 bytes
lambda b:max(reduce(set.__and__,[d[f:e]for e in range(len(d)+2)for f in range(e)for d in b]),key=len)
Try it online!
This is an anonymous lambda that transforms each element into the set of all substrings, then reduce
s it by set intersection (set.__and__
) and then returns the max
element by len
gth.
$endgroup$
add a comment |
$begingroup$
JavaScript (Node.js), 106 bytes
This assumes presence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.indexOf(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
JavaScript (Node.js), 114 105 bytes
This assumes absence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
Probably still golfable.
$endgroup$
add a comment |
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8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Jelly, 12 bytes
Ẇ€œ&/LÐṀḢ¹L?
Try it online!
Last four bytes are there because of the requirement to only output one answer.
$endgroup$
add a comment |
$begingroup$
Jelly, 12 bytes
Ẇ€œ&/LÐṀḢ¹L?
Try it online!
Last four bytes are there because of the requirement to only output one answer.
$endgroup$
add a comment |
$begingroup$
Jelly, 12 bytes
Ẇ€œ&/LÐṀḢ¹L?
Try it online!
Last four bytes are there because of the requirement to only output one answer.
$endgroup$
Jelly, 12 bytes
Ẇ€œ&/LÐṀḢ¹L?
Try it online!
Last four bytes are there because of the requirement to only output one answer.
answered 1 hour ago
Nick KennedyNick Kennedy
92147
92147
add a comment |
add a comment |
$begingroup$
Brachylog (v2), 3 bytes
sᵛw
Try it online!
Full program. Input from standard input (as a JSON-style list of strings), output to standard output.
Explanation
sᵛw
s Find a substring
ᵛ of every element of the input; the same one for each
w and output it.
Tiebreak order here is set by the s
, favouring the longest substring (the secondary tiebreak doesn't matter, but IIRC it's position within the first element of the input).
Brachylog's s
doesn't return empty substrings, so we need a bit of a trick to get around that: instead of making a function submission (which is what's normally done), we write a full program, outputting to standard output. That way, if there's a common substring, we just output it, and we're done. If there isn't a common substring, the program errors out – but it still prints nothing to standard output, thus it outputs the null string as intended.
$endgroup$
add a comment |
$begingroup$
Brachylog (v2), 3 bytes
sᵛw
Try it online!
Full program. Input from standard input (as a JSON-style list of strings), output to standard output.
Explanation
sᵛw
s Find a substring
ᵛ of every element of the input; the same one for each
w and output it.
Tiebreak order here is set by the s
, favouring the longest substring (the secondary tiebreak doesn't matter, but IIRC it's position within the first element of the input).
Brachylog's s
doesn't return empty substrings, so we need a bit of a trick to get around that: instead of making a function submission (which is what's normally done), we write a full program, outputting to standard output. That way, if there's a common substring, we just output it, and we're done. If there isn't a common substring, the program errors out – but it still prints nothing to standard output, thus it outputs the null string as intended.
$endgroup$
add a comment |
$begingroup$
Brachylog (v2), 3 bytes
sᵛw
Try it online!
Full program. Input from standard input (as a JSON-style list of strings), output to standard output.
Explanation
sᵛw
s Find a substring
ᵛ of every element of the input; the same one for each
w and output it.
Tiebreak order here is set by the s
, favouring the longest substring (the secondary tiebreak doesn't matter, but IIRC it's position within the first element of the input).
Brachylog's s
doesn't return empty substrings, so we need a bit of a trick to get around that: instead of making a function submission (which is what's normally done), we write a full program, outputting to standard output. That way, if there's a common substring, we just output it, and we're done. If there isn't a common substring, the program errors out – but it still prints nothing to standard output, thus it outputs the null string as intended.
$endgroup$
Brachylog (v2), 3 bytes
sᵛw
Try it online!
Full program. Input from standard input (as a JSON-style list of strings), output to standard output.
Explanation
sᵛw
s Find a substring
ᵛ of every element of the input; the same one for each
w and output it.
Tiebreak order here is set by the s
, favouring the longest substring (the secondary tiebreak doesn't matter, but IIRC it's position within the first element of the input).
Brachylog's s
doesn't return empty substrings, so we need a bit of a trick to get around that: instead of making a function submission (which is what's normally done), we write a full program, outputting to standard output. That way, if there's a common substring, we just output it, and we're done. If there isn't a common substring, the program errors out – but it still prints nothing to standard output, thus it outputs the null string as intended.
answered 57 mins ago
community wiki
ais523
add a comment |
add a comment |
$begingroup$
Python 3, 137 bytes
def a(b):c=[[d[f:e]for e in range(len(d)+1)for f in range(e+1)]for d in b];return max([i for i in c[0]if all(i in j for j in c)],key=len)
Try it online!
New contributor
$endgroup$
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
$endgroup$
– Shieru Asakoto
1 hour ago
$begingroup$
@ShieruAsakoto Oops yeah.
$endgroup$
– Artemis Fowl
1 hour ago
$begingroup$
@JoKing tio.run/…
$endgroup$
– Artemis Fowl
39 mins ago
$begingroup$
@JoKing The one currently in my answer is fine for all the test cases.
$endgroup$
– Artemis Fowl
33 mins ago
$begingroup$
Right, here's a fixed version of the 135 byte program
$endgroup$
– Jo King
29 mins ago
add a comment |
$begingroup$
Python 3, 137 bytes
def a(b):c=[[d[f:e]for e in range(len(d)+1)for f in range(e+1)]for d in b];return max([i for i in c[0]if all(i in j for j in c)],key=len)
Try it online!
New contributor
$endgroup$
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
$endgroup$
– Shieru Asakoto
1 hour ago
$begingroup$
@ShieruAsakoto Oops yeah.
$endgroup$
– Artemis Fowl
1 hour ago
$begingroup$
@JoKing tio.run/…
$endgroup$
– Artemis Fowl
39 mins ago
$begingroup$
@JoKing The one currently in my answer is fine for all the test cases.
$endgroup$
– Artemis Fowl
33 mins ago
$begingroup$
Right, here's a fixed version of the 135 byte program
$endgroup$
– Jo King
29 mins ago
add a comment |
$begingroup$
Python 3, 137 bytes
def a(b):c=[[d[f:e]for e in range(len(d)+1)for f in range(e+1)]for d in b];return max([i for i in c[0]if all(i in j for j in c)],key=len)
Try it online!
New contributor
$endgroup$
Python 3, 137 bytes
def a(b):c=[[d[f:e]for e in range(len(d)+1)for f in range(e+1)]for d in b];return max([i for i in c[0]if all(i in j for j in c)],key=len)
Try it online!
New contributor
edited 29 mins ago
New contributor
answered 1 hour ago
Artemis FowlArtemis Fowl
1013
1013
New contributor
New contributor
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
$endgroup$
– Shieru Asakoto
1 hour ago
$begingroup$
@ShieruAsakoto Oops yeah.
$endgroup$
– Artemis Fowl
1 hour ago
$begingroup$
@JoKing tio.run/…
$endgroup$
– Artemis Fowl
39 mins ago
$begingroup$
@JoKing The one currently in my answer is fine for all the test cases.
$endgroup$
– Artemis Fowl
33 mins ago
$begingroup$
Right, here's a fixed version of the 135 byte program
$endgroup$
– Jo King
29 mins ago
add a comment |
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
$endgroup$
– Shieru Asakoto
1 hour ago
$begingroup$
@ShieruAsakoto Oops yeah.
$endgroup$
– Artemis Fowl
1 hour ago
$begingroup$
@JoKing tio.run/…
$endgroup$
– Artemis Fowl
39 mins ago
$begingroup$
@JoKing The one currently in my answer is fine for all the test cases.
$endgroup$
– Artemis Fowl
33 mins ago
$begingroup$
Right, here's a fixed version of the 135 byte program
$endgroup$
– Jo King
29 mins ago
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
$endgroup$
– Shieru Asakoto
1 hour ago
$begingroup$
You may want to use single spaces as indentation instead of 4 that seems to shave more than 100 bytes.
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– Shieru Asakoto
1 hour ago
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@ShieruAsakoto Oops yeah.
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– Artemis Fowl
1 hour ago
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@ShieruAsakoto Oops yeah.
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– Artemis Fowl
1 hour ago
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@JoKing tio.run/…
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– Artemis Fowl
39 mins ago
$begingroup$
@JoKing tio.run/…
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– Artemis Fowl
39 mins ago
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@JoKing The one currently in my answer is fine for all the test cases.
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– Artemis Fowl
33 mins ago
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@JoKing The one currently in my answer is fine for all the test cases.
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– Artemis Fowl
33 mins ago
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Right, here's a fixed version of the 135 byte program
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– Jo King
29 mins ago
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Right, here's a fixed version of the 135 byte program
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– Jo King
29 mins ago
add a comment |
$begingroup$
Perl 6, 62 bytes
~sort(-*.comb,keys [∩] .map(*.comb[^*X.. ^*+1]>>.join))[0]
Try it online!
I'm a little annoyed the Perl 6 can't do set operations on lists of lists, which is why there's an extra .comb
and >>
in there. Another annoying thing is that max
can't take an function for how to compare items, meaning I have to user sort
instead.
$endgroup$
add a comment |
$begingroup$
Perl 6, 62 bytes
~sort(-*.comb,keys [∩] .map(*.comb[^*X.. ^*+1]>>.join))[0]
Try it online!
I'm a little annoyed the Perl 6 can't do set operations on lists of lists, which is why there's an extra .comb
and >>
in there. Another annoying thing is that max
can't take an function for how to compare items, meaning I have to user sort
instead.
$endgroup$
add a comment |
$begingroup$
Perl 6, 62 bytes
~sort(-*.comb,keys [∩] .map(*.comb[^*X.. ^*+1]>>.join))[0]
Try it online!
I'm a little annoyed the Perl 6 can't do set operations on lists of lists, which is why there's an extra .comb
and >>
in there. Another annoying thing is that max
can't take an function for how to compare items, meaning I have to user sort
instead.
$endgroup$
Perl 6, 62 bytes
~sort(-*.comb,keys [∩] .map(*.comb[^*X.. ^*+1]>>.join))[0]
Try it online!
I'm a little annoyed the Perl 6 can't do set operations on lists of lists, which is why there's an extra .comb
and >>
in there. Another annoying thing is that max
can't take an function for how to compare items, meaning I have to user sort
instead.
answered 12 mins ago
Jo KingJo King
25.3k361129
25.3k361129
add a comment |
add a comment |
$begingroup$
Japt v2.0a0, 24 bytes
mã c f@eøXÃr@XÊ>YÊ?X:Y}P
This is a mess. Why isn't there a max function for arrays in Japt?
Try it online!
$endgroup$
add a comment |
$begingroup$
Japt v2.0a0, 24 bytes
mã c f@eøXÃr@XÊ>YÊ?X:Y}P
This is a mess. Why isn't there a max function for arrays in Japt?
Try it online!
$endgroup$
add a comment |
$begingroup$
Japt v2.0a0, 24 bytes
mã c f@eøXÃr@XÊ>YÊ?X:Y}P
This is a mess. Why isn't there a max function for arrays in Japt?
Try it online!
$endgroup$
Japt v2.0a0, 24 bytes
mã c f@eøXÃr@XÊ>YÊ?X:Y}P
This is a mess. Why isn't there a max function for arrays in Japt?
Try it online!
answered 10 mins ago
Embodiment of IgnoranceEmbodiment of Ignorance
2,138125
2,138125
add a comment |
add a comment |
$begingroup$
Zsh, 126 bytes
for l in $@
a=
for i in 0..$[$#l**2]
a+=($l[1+i/$#l,1+i%$#l])
b=($$b-$a:*a)
for i in $b
(($#x<$#i))&&x=$i
<<<$x
Try it online!
We read all possible substrings into $a
, and then intersect the common elements of $a
and $b
.
for l in $@;
a= # unset a
for i in 0..$[$#l**2]; # compound double loop using div/mod
a+=( $l[1+i/$#l,1+i%$#l] ) # append to a all possible substrings of the given line
b=( $$b-$a:*a )
# $b-$a # if b is unset substitute $a
# $ :*a # take common elements of $b-$a and $a
# b=( ) # set b to those elements
for i in $b; # for every common substring
(( $#x < $#i ))&&x=$i # if the current word is longer, use it
<<<$x # print to stdout
New contributor
$endgroup$
add a comment |
$begingroup$
Zsh, 126 bytes
for l in $@
a=
for i in 0..$[$#l**2]
a+=($l[1+i/$#l,1+i%$#l])
b=($$b-$a:*a)
for i in $b
(($#x<$#i))&&x=$i
<<<$x
Try it online!
We read all possible substrings into $a
, and then intersect the common elements of $a
and $b
.
for l in $@;
a= # unset a
for i in 0..$[$#l**2]; # compound double loop using div/mod
a+=( $l[1+i/$#l,1+i%$#l] ) # append to a all possible substrings of the given line
b=( $$b-$a:*a )
# $b-$a # if b is unset substitute $a
# $ :*a # take common elements of $b-$a and $a
# b=( ) # set b to those elements
for i in $b; # for every common substring
(( $#x < $#i ))&&x=$i # if the current word is longer, use it
<<<$x # print to stdout
New contributor
$endgroup$
add a comment |
$begingroup$
Zsh, 126 bytes
for l in $@
a=
for i in 0..$[$#l**2]
a+=($l[1+i/$#l,1+i%$#l])
b=($$b-$a:*a)
for i in $b
(($#x<$#i))&&x=$i
<<<$x
Try it online!
We read all possible substrings into $a
, and then intersect the common elements of $a
and $b
.
for l in $@;
a= # unset a
for i in 0..$[$#l**2]; # compound double loop using div/mod
a+=( $l[1+i/$#l,1+i%$#l] ) # append to a all possible substrings of the given line
b=( $$b-$a:*a )
# $b-$a # if b is unset substitute $a
# $ :*a # take common elements of $b-$a and $a
# b=( ) # set b to those elements
for i in $b; # for every common substring
(( $#x < $#i ))&&x=$i # if the current word is longer, use it
<<<$x # print to stdout
New contributor
$endgroup$
Zsh, 126 bytes
for l in $@
a=
for i in 0..$[$#l**2]
a+=($l[1+i/$#l,1+i%$#l])
b=($$b-$a:*a)
for i in $b
(($#x<$#i))&&x=$i
<<<$x
Try it online!
We read all possible substrings into $a
, and then intersect the common elements of $a
and $b
.
for l in $@;
a= # unset a
for i in 0..$[$#l**2]; # compound double loop using div/mod
a+=( $l[1+i/$#l,1+i%$#l] ) # append to a all possible substrings of the given line
b=( $$b-$a:*a )
# $b-$a # if b is unset substitute $a
# $ :*a # take common elements of $b-$a and $a
# b=( ) # set b to those elements
for i in $b; # for every common substring
(( $#x < $#i ))&&x=$i # if the current word is longer, use it
<<<$x # print to stdout
New contributor
New contributor
answered 3 mins ago
GammaFunctionGammaFunction
615
615
New contributor
New contributor
add a comment |
add a comment |
$begingroup$
Python 2, 103 bytes
lambda b:max(reduce(set.__and__,[d[f:e]for e in range(len(d)+2)for f in range(e)for d in b]),key=len)
Try it online!
This is an anonymous lambda that transforms each element into the set of all substrings, then reduce
s it by set intersection (set.__and__
) and then returns the max
element by len
gth.
$endgroup$
add a comment |
$begingroup$
Python 2, 103 bytes
lambda b:max(reduce(set.__and__,[d[f:e]for e in range(len(d)+2)for f in range(e)for d in b]),key=len)
Try it online!
This is an anonymous lambda that transforms each element into the set of all substrings, then reduce
s it by set intersection (set.__and__
) and then returns the max
element by len
gth.
$endgroup$
add a comment |
$begingroup$
Python 2, 103 bytes
lambda b:max(reduce(set.__and__,[d[f:e]for e in range(len(d)+2)for f in range(e)for d in b]),key=len)
Try it online!
This is an anonymous lambda that transforms each element into the set of all substrings, then reduce
s it by set intersection (set.__and__
) and then returns the max
element by len
gth.
$endgroup$
Python 2, 103 bytes
lambda b:max(reduce(set.__and__,[d[f:e]for e in range(len(d)+2)for f in range(e)for d in b]),key=len)
Try it online!
This is an anonymous lambda that transforms each element into the set of all substrings, then reduce
s it by set intersection (set.__and__
) and then returns the max
element by len
gth.
answered 2 mins ago
Jo KingJo King
25.3k361129
25.3k361129
add a comment |
add a comment |
$begingroup$
JavaScript (Node.js), 106 bytes
This assumes presence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.indexOf(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
JavaScript (Node.js), 114 105 bytes
This assumes absence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
Probably still golfable.
$endgroup$
add a comment |
$begingroup$
JavaScript (Node.js), 106 bytes
This assumes presence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.indexOf(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
JavaScript (Node.js), 114 105 bytes
This assumes absence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
Probably still golfable.
$endgroup$
add a comment |
$begingroup$
JavaScript (Node.js), 106 bytes
This assumes presence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.indexOf(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
JavaScript (Node.js), 114 105 bytes
This assumes absence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
Probably still golfable.
$endgroup$
JavaScript (Node.js), 106 bytes
This assumes presence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.indexOf(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
JavaScript (Node.js), 114 105 bytes
This assumes absence of regex special characters.
a=>(F=(l,n,w=a[0].substr(n,l))=>l?n<0?F(--l,L-l):a.some(y=>y.search(w)<0)?F(l,n-1):w:"")(L=a[0].length,0)
Try it online!
Probably still golfable.
edited 1 min ago
answered 1 hour ago
Shieru AsakotoShieru Asakoto
2,750317
2,750317
add a comment |
add a comment |
If this is an answer to a challenge…
…Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.
…Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one.
Explanations of your answer make it more interesting to read and are very much encouraged.…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.
More generally…
…Please make sure to answer the question and provide sufficient detail.
…Avoid asking for help, clarification or responding to other answers (use comments instead).
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$begingroup$
Possible duplicate
$endgroup$
– Adám
2 hours ago
$begingroup$
@Adám That question asks for the longest common subsequence, not substring.
$endgroup$
– Doorknob♦
2 hours ago
1
$begingroup$
Will the strings be only alphanumeric, or alphabetic, or only printable-ascii?
$endgroup$
– Embodiment of Ignorance
1 hour ago
$begingroup$
@EmbodimentofIgnorance All printable ASCII characters can appear in the input.
$endgroup$
– Sara J
48 mins ago