Expectation in a stochastic differential equation The Next CEO of Stack OverflowWhat is Ito's lemma used for in quantitative finance?Question about the stochastic differential equation in the Merton modelComputation of ExpectationSquare of arithmetic brownian motion processBaxter & Rennie HJM: differentiating Ito integralSimple HJM model, differentiating the bond priceStochastic Leibniz ruleStochastic differential equation of a Brownian MotionHow to calculate the product of forward rates with different reset times using Ito's lemma?For an Ito Process, $dlnX neq fracdXX$ and $(dlnX)^2 = (fracdXX)^2$, but $dlnX neq pm fracdXX$

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Expectation in a stochastic differential equation



The Next CEO of Stack OverflowWhat is Ito's lemma used for in quantitative finance?Question about the stochastic differential equation in the Merton modelComputation of ExpectationSquare of arithmetic brownian motion processBaxter & Rennie HJM: differentiating Ito integralSimple HJM model, differentiating the bond priceStochastic Leibniz ruleStochastic differential equation of a Brownian MotionHow to calculate the product of forward rates with different reset times using Ito's lemma?For an Ito Process, $dlnX neq fracdXX$ and $(dlnX)^2 = (fracdXX)^2$, but $dlnX neq pm fracdXX$










2












$begingroup$


I'm new to stochastic calculus, I want to find the mean of $X_2$ with $X_t = exp(W_t)$, with $W_t$ a Wiener process.



I used Ito's Lemma is arrive at the SDE:
beginalign
d(X_t) = frac12X_t dt + X_t dW_t
endalign

But how can I get the mean of $X_2$?










share|improve this question











$endgroup$
















    2












    $begingroup$


    I'm new to stochastic calculus, I want to find the mean of $X_2$ with $X_t = exp(W_t)$, with $W_t$ a Wiener process.



    I used Ito's Lemma is arrive at the SDE:
    beginalign
    d(X_t) = frac12X_t dt + X_t dW_t
    endalign

    But how can I get the mean of $X_2$?










    share|improve this question











    $endgroup$














      2












      2








      2


      1



      $begingroup$


      I'm new to stochastic calculus, I want to find the mean of $X_2$ with $X_t = exp(W_t)$, with $W_t$ a Wiener process.



      I used Ito's Lemma is arrive at the SDE:
      beginalign
      d(X_t) = frac12X_t dt + X_t dW_t
      endalign

      But how can I get the mean of $X_2$?










      share|improve this question











      $endgroup$




      I'm new to stochastic calculus, I want to find the mean of $X_2$ with $X_t = exp(W_t)$, with $W_t$ a Wiener process.



      I used Ito's Lemma is arrive at the SDE:
      beginalign
      d(X_t) = frac12X_t dt + X_t dW_t
      endalign

      But how can I get the mean of $X_2$?







      itos-lemma sde






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago







      Victor

















      asked 2 hours ago









      VictorVictor

      614




      614




















          1 Answer
          1






          active

          oldest

          votes


















          1












          $begingroup$

          Assuming you are talking about unconditional expectation, in general you have



          $$
          mathbbE[X_t] = mathbbE[e^W_t] = e^mathbbE[W_t] + frac12textVar(W_t)
          $$



          which yields



          $$
          mathbbE[X_t]= e^frac12 t
          $$



          Hence,



          $$ mathbbE[X_2]= e $$






          share|improve this answer








          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$












          • $begingroup$
            I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
            $endgroup$
            – Victor
            1 hour ago






          • 1




            $begingroup$
            @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
            $endgroup$
            – RafaelC
            1 hour ago











          Your Answer





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          1 Answer
          1






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          1 Answer
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          active

          oldest

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          active

          oldest

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          1












          $begingroup$

          Assuming you are talking about unconditional expectation, in general you have



          $$
          mathbbE[X_t] = mathbbE[e^W_t] = e^mathbbE[W_t] + frac12textVar(W_t)
          $$



          which yields



          $$
          mathbbE[X_t]= e^frac12 t
          $$



          Hence,



          $$ mathbbE[X_2]= e $$






          share|improve this answer








          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$












          • $begingroup$
            I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
            $endgroup$
            – Victor
            1 hour ago






          • 1




            $begingroup$
            @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
            $endgroup$
            – RafaelC
            1 hour ago















          1












          $begingroup$

          Assuming you are talking about unconditional expectation, in general you have



          $$
          mathbbE[X_t] = mathbbE[e^W_t] = e^mathbbE[W_t] + frac12textVar(W_t)
          $$



          which yields



          $$
          mathbbE[X_t]= e^frac12 t
          $$



          Hence,



          $$ mathbbE[X_2]= e $$






          share|improve this answer








          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$












          • $begingroup$
            I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
            $endgroup$
            – Victor
            1 hour ago






          • 1




            $begingroup$
            @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
            $endgroup$
            – RafaelC
            1 hour ago













          1












          1








          1





          $begingroup$

          Assuming you are talking about unconditional expectation, in general you have



          $$
          mathbbE[X_t] = mathbbE[e^W_t] = e^mathbbE[W_t] + frac12textVar(W_t)
          $$



          which yields



          $$
          mathbbE[X_t]= e^frac12 t
          $$



          Hence,



          $$ mathbbE[X_2]= e $$






          share|improve this answer








          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$



          Assuming you are talking about unconditional expectation, in general you have



          $$
          mathbbE[X_t] = mathbbE[e^W_t] = e^mathbbE[W_t] + frac12textVar(W_t)
          $$



          which yields



          $$
          mathbbE[X_t]= e^frac12 t
          $$



          Hence,



          $$ mathbbE[X_2]= e $$







          share|improve this answer








          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          share|improve this answer



          share|improve this answer






          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          answered 1 hour ago









          RafaelCRafaelC

          1263




          1263




          New contributor




          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          New contributor





          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          RafaelC is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.











          • $begingroup$
            I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
            $endgroup$
            – Victor
            1 hour ago






          • 1




            $begingroup$
            @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
            $endgroup$
            – RafaelC
            1 hour ago
















          • $begingroup$
            I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
            $endgroup$
            – Victor
            1 hour ago






          • 1




            $begingroup$
            @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
            $endgroup$
            – RafaelC
            1 hour ago















          $begingroup$
          I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
          $endgroup$
          – Victor
          1 hour ago




          $begingroup$
          I'm quite new to the theory. What is the name of the first equality and under which hypotheses is it true?
          $endgroup$
          – Victor
          1 hour ago




          1




          1




          $begingroup$
          @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
          $endgroup$
          – RafaelC
          1 hour ago




          $begingroup$
          @Victor the first equality comes from the moment-generating function of a normal. Take a look here for more details. In general, $mathbbE[e^X] = e^mu + frac12 sigma^2$ holds whenever $X sim mathcalN(mu, sigma^2)$
          $endgroup$
          – RafaelC
          1 hour ago

















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