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Check if object is null and return null
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Check if object is null and return null
2019 Community Moderator Electionhow to check if limit is approaching in my triggerRunning a child query on Person AccountsWhat reasons would the id in URL be null?deserializing JSON returns a null objectReturn SOQL for current record on Visualforce EmailBest Practices : Page Reference method return nullSOQL Select in test setup?Check isEmpty OR Catch ListException?Ajax REST Tooling Queries Return Null SymbolTable?“Attempt to de-reference a null object” on VF page
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
asked 1 hour ago
ebarebar
132
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
asked 1 hour ago
ebarebar
132
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
asked 1 hour ago
ebarebar
132
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null)
return null;
apex visualforce visualforce-component
apex visualforce visualforce-component
asked 1 hour ago
ebarebar
132
asked 1 hour ago
ebarebar
132
asked 1 hour ago
ebarebar
132
asked 1 hour ago
ebarebar
132
asked 1 hour ago
ebarebar
132
132
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 1 hour ago
Keith CKeith C
96.1k1094212
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 1 hour ago
Phil WPhil W
471210
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 1 hour ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 1 hour ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 1 hour ago
Keith CKeith C
96.1k1094212
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 1 hour ago
Keith CKeith C
96.1k1094212
answered 1 hour ago
Keith CKeith C
96.1k1094212
answered 1 hour ago
Keith CKeith C
96.1k1094212
answered 1 hour ago
Keith CKeith C
96.1k1094212
96.1k1094212
add a comment |
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1])
person = record;
return person; // will return null or a single record
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
answered 1 hour ago
sfdcfoxsfdcfox
260k12205450
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
add a comment |
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
1 hour ago
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 1 hour ago
Phil WPhil W
471210
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 1 hour ago
Phil WPhil W
471210
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 1 hour ago
Phil WPhil W
471210
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0)
return null;
else
return people[0];
answered 1 hour ago
Phil WPhil W
471210
answered 1 hour ago
Phil WPhil W
471210
answered 1 hour ago
Phil WPhil W
471210
answered 1 hour ago
Phil WPhil W
471210
471210
add a comment |
add a comment |
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